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12.88t^2+5t=25
We move all terms to the left:
12.88t^2+5t-(25)=0
a = 12.88; b = 5; c = -25;
Δ = b2-4ac
Δ = 52-4·12.88·(-25)
Δ = 1313
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{1313}}{2*12.88}=\frac{-5-\sqrt{1313}}{25.76} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{1313}}{2*12.88}=\frac{-5+\sqrt{1313}}{25.76} $
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